9v^2-3v-20=3v(3v+5)-4(3v+5)

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Solution for 9v^2-3v-20=3v(3v+5)-4(3v+5) equation: 



9v^2-3v-20=3v(3v+5)-4(3v+5)

We move all terms to the left:

9v^2-3v-20-(3v(3v+5)-4(3v+5))=0



We calculate terms in parentheses: -(3v(3v+5)-4(3v+5)), so:

3v(3v+5)-4(3v+5)

We multiply parentheses

9v^2+15v-12v-20

We add all the numbers together, and all the variables

9v^2+3v-20

Back to the equation:

-(9v^2+3v-20)



We get rid of parentheses

9v^2-9v^2-3v-3v+20-20=0

We add all the numbers together, and all the variables

-6v=0

v=0/-6

v=0

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